看闰年的C程序

seablue

源代码：

1. 
   
2. [linuxer@mydesktop bmp]$ cat year.c
   
3. #include "stdio.h"
   
4. main()
   
5. {int year;
   
6. printf("\n1900-2100的闰年有：\n\n");
   
7. for(year=1900;year<=2100;year++)
   
8. if((year%4==0&&year%100!=0)||(year%400==0))printf("%d,",year);
   
9. printf("\n\n1900-2100的平年有：\n\n");
   
10. for(year=1900;year<=2100;year++)
    
11. if(!((year%4==0&&year%100!=0)||(year%400==0)))printf("%d,",year);
    
12. }
    
13. [linuxer@mydesktop bmp]$
    

复制代码

编译与运行：

1. 
   
2. [linuxer@mydesktop bmp]$ gcc -o year.o year.c
   
3. [linuxer@mydesktop bmp]$ ./year.o
   
4. 
   
5. 1900-2100的闰年有：
   
6. 
   
7. 1904,1908,1912,1916,1920,1924,1928,1932,1936,1940,1944,1948,1952,
   
8. 1956,1960,1964,1968,1972,1976,1980,1984,1988,1992,1996,2000,2004,
   
9. 2008,2012,2016,2020,2024,2028,2032,2036,2040,2044,2048,2052,2056,
   
10. 2060,2064,2068,2072,2076,2080,2084,2088,2092,2096,
    
11. 
    
12. 1900-2100的平年有：
    
13. 
    
14. 1900,1901,1902,1903,1905,1906,1907,1909,1910,1911,1913,1914,1915,
    
15. 1917,1918,1919,1921,1922,1923,1925,1926,1927,1929,1930,1931,1933,
    
16. 1934,1935,1937,1938,1939,1941,1942,1943,1945,1946,1947,1949,1950,
    
17. 1951,1953,1954,1955,1957,1958,1959,1961,1962,1963,1965,1966,1967,
    
18. 1969,1970,1971,1973,1974,1975,1977,1978,1979,1981,1982,1983,1985,
    
19. 1986,1987,1989,1990,1991,1993,1994,1995,1997,1998,1999,2001,2002,
    
20. 2003,2005,2006,2007,2009,2010,2011,2013,2014,2015,2017,2018,2019,
    
21. 2021,2022,2023,2025,2026,2027,2029,2030,2031,2033,2034,2035,2037,
    
22. 2038,2039,2041,2042,2043,2045,2046,2047,2049,2050,2051,2053,2054,
    
23. 2055,2057,2058,2059,2061,2062,2063,2065,2066,2067,2069,2070,2071,
    
24. 2073,2074,2075,2077,2078,2079,2081,2082,2083,2085,2086,2087,2089,
    
25. 2090,2091,2093,2094,2095,2097,2098,2099,2100,
    
26. [linuxer@mydesktop bmp]$
    

复制代码

Linux_Lyb

goooood!!

ajinn

最初由 Linux_Lyb 发表
goooood!!

灌水嫌疑

devel

有谁说说闰年的知识阿。。。。我看了网上说能整除四的一年就时闰年。。。但看大家的概念都不同呢:confused: :confused:

pupilzeng

最初由 devel 发表
有谁说说闰年的知识阿。。。。我看了网上说能整除四的一年就时闰年。。。但看大家的概念都不同呢:confused: :confused:

现行公历历法400年中有97个闰年，这样算下去，3000多年会有一天的误差。
97个闰年是这样分布的：

1. 
   
2. if((year % 4 == 0 && year % 100 != 0)
   
3.     || (year % 400 == 0))
   
4. {
   
5.           /* leap year */
   
6. }
   
7. else
   
8. {
   
9.          /*non-leap year*/
   
10. }
    

复制代码

这样的话，每400年中前三个能被100整除的年份，都不是闰年，所以闰年的个数刚好是100-3 = 97。

seablue

贴个比较完整的，可以接受输入任何年份：

1. 
   
2. /* 显示闰年、平年的C代码
   
3. // 接受两个变量a，b作为起止年份。
   
4. //gcc (GCC) 3.2.2 20030222 (Red Hat Linux 3.2.2-5)
   
5. //    version 0.10
   
6. //     2004-05-07
   
7. // By seablue at linuxsir.cn
   
8. */
   
9. 
   
10. #include <stdio.h>
    
11. main()
    
12. {int a,b,i,k,t;
    
13. printf("Please input year of beginning and year of end:\n");
    
14. printf("Example: 1900 2000\n");
    
15. 
    
16. /*输入起止年份，并让a＜b
    
17. */
    
18. scanf("%d %d",&a,&b);
    
19. if(a>b){t=a;a=b;b=t;}
    
20. 
    
21. /*输出闰年及其总数
    
22. */
    
23. printf("\nLeapyear of %d-%d:\n",a,b);
    
24. for(i=a,k=0;i<=b;i++)
    
25. if((i%4==0&&i%100!=0)||(i%400==0)){k++;printf("%d,",i);}
    
26. printf("\b.\nTotall: %d\n\nNon-leapyear of %d-%d:\n",k,a,b);
    
27. 
    
28. /*输出平年及其总数
    
29. */
    
30. for(i=a,k=0;i<=b;i++)
    
31. if(!((i%4==0&&i%100!=0)||(i%400==0))){k++;printf("%d,",i);}
    
32. printf("\b.\nTotall: %d\n",k);
    
33. }
    

复制代码